Actuarial Notes

Exam MAS-I Practice Question 155

Study guide: Exam MAS-I

A Poisson claim-frequency GLM gives a coastal-territory coefficient of 0.30 with standard error 0.125, a Wald statistic of 2.4. Pearson's chi-square statistic divided by the residual degrees of freedom is 2.25, so the actuary refits the model as quasi-Poisson with \text{Var}(Y) = \phi\mu and \hat\phi = 2.25.

Which of the following describes the coastal-territory row of the quasi-Poisson output?

  • A) Estimate 0.133; standard error 0.125; test statistic 1.07
  • B) Estimate 0.30; standard error 0.281; test statistic 1.07
  • C) Estimate 0.20; standard error 0.083; test statistic 2.40
  • D) Estimate 0.30; standard error 0.083; test statistic 3.60
  • E) Estimate 0.30; standard error 0.188; test statistic 1.60

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