Term of Annuity
Study guide: Exam FM-2
The term of an annuity is the fixed period of time over which its payments are made, measured in payment periods: an annuity of n payments, one per period, has a term of n periods. For an annuity-immediate the term runs from one period before the first payment to the last payment; for an annuity-due, from the first payment to one period after the last. A 30-year monthly mortgage has a term of 360 months.
- In the annuity factor
a_{\overline{n}|i},nis the term — the number of payment periods. - Given the present value, the level payment
Pand the ratei, the term of an annuity-immediate is found with logarithms:
n = \frac{\ln(1 - i \cdot \text{PV}/P)}{\ln(1/(1+i))}
= \frac{-\ln(1 - i \cdot \text{PV}/P)}{\ln(1+i)}
- For an annuity-due,
\text{PV} = P\,\ddot{a}_{\overline{n}|} = P(1-v^n)/d, so replaceibydinside the logarithm:n = -\ln(1 - d \cdot \text{PV}/P)/\ln(1+i). - When
nis not a whole number,\lfloor n \rfloorregular payments are made plus one smaller payment — added to the last regular payment (a balloon payment) or made one period after it (a drop payment). - A Perpetuity is an annuity with an infinite term.
Solving for Unknown Term A $10,000 loan at
6\%is repaid with level annual payments of $1,500, the first one year from now, for as long as needed, followed by a smaller final payment one year after the last regular one. How many regular payments are made, and how large is the final payment?Answer
\begin{align*} a_{\overline{n}|} &= \frac{10{,}000}{1{,}500} \\ &= 6.666667 \\ n &= \frac{-\ln(1 - 0.06 \times 6.666667)}{\ln(1.06)} \\ &= \frac{-\ln(0.60)}{0.0582689} \\ &= \frac{0.5108256}{0.0582689} \\ &= 8.77 \end{align*}So 8 regular payments are made, and a smaller ninth at time 9 — a drop payment. It is the balance just after the 8th payment, carried one more year:
\begin{align*} OB_8 &= 10{,}000(1.06)^8 - 1{,}500\,s_{\overline{8}|} \\ &= 15{,}938.48 - 1{,}500(9.897468) \\ &= 15{,}938.48 - 14{,}846.20 \\ &= 1{,}092.28 \\ \text{Drop} &= 1{,}092.28 \times 1.06 \\ &= 1{,}157.82 \end{align*}Check:
1{,}500\,a_{\overline{8}|} + 1{,}157.82\,v^9 = 9{,}314.69 + 685.31 = 10{,}000.