Actuarial Notes

Continuous Univariate Distributions

Study guide: Exam P-1

A Continuous Univariate Distribution describes the probability law of a single random variable X that can take any value in a continuous interval or union of continuous intervals.

  • The probability density function (PDF) f(x) must satisfy f(x) \geq 0 and \int_{-\infty}^{\infty} f(x)\,dx = 1
  • Individual point probabilities are zero; all probabilities are computed as areas under f:

P(a \leq X \leq b) = \int_a^b f(x)\, dx

  • The CDF and the density are two views of the same object: F(x) = \int_{-\infty}^{x} f(t)\,dt and f(x) = F'(x). For anything phrased as a tail probability, work from the survival function S(x) = 1 - F(x) instead.

Choosing the right one

Read the question for the story the quantity follows, then check the support matches:

  • Every value in a range equally likely → Uniform Continuous Distribution (a,b) on (a,b), with E[X] = (a+b)/2

  • Waiting time between events, memoryless → Exponential Distribution (\theta) on (0,\infty), with E[X] = \theta

  • Waiting time to the \alpha-th event, or a skewed severity → Gamma (\alpha,\theta) on (0,\infty), with E[X] = \alpha\theta

  • A proportion, rate, or probability → Beta (\alpha,\beta) on (0,1), with E[X] = \alpha/(\alpha+\beta)

  • A sum or average of many variables → Normal Distribution (\mu,\sigma^2) on \mathbb{R}, with E[X] = \mu

  • A positive, heavily right-skewed loss whose log is normal → Lognormal Distribution (\mu,\sigma^2) on (0,\infty), with E[X] = e^{\mu+\sigma^2/2}

  • The word memoryless is decisive: it appears only for the exponential (and its discrete counterpart, the geometric).

  • For the lognormal, \mu and \sigma are the parameters of \ln X, not the mean and standard deviation of X. Every lognormal probability reduces to a normal one by taking logs of both sides: P(X > c) = P(\ln X > \ln c).

  • Apart from a uniform with a < 0, the normal is the only one on this list that can go negative, and the only one with no lower bound at all — a red flag if the quantity is a loss.

  • Insurance provisions (deductibles, limits, coinsurance) transform whichever severity distribution is chosen; see Transformations of Random Variables.

Finding a Probability from a PDF A random variable X has PDF f(x) = 3x^2 for 0 < x < 1. Find P(0.5 < X < 1).

Answer P(0.5 < X < 1) = \int_{0.5}^{1} 3x^2\, dx = \left[x^3\right]_{0.5}^{1} = 1 - (0.5)^3 = 1 - 0.125 = 0.875