Tail Factor
Study guide: Exam 5
Tail Factor is the development factor applied beyond the last maturity observable in the triangle — the estimate of all emergence that will occur after the data runs out.
\text{CDF}_{\text{last age} \to \text{ult}} = f_{\text{last observed}} \times \text{Tail}
- The tail is the one factor with no data behind it, and in long-tail lines it is often the single largest assumption in the analysis. A triangle that runs ten years still misses decades of workers compensation medical payments.
- Methods for selecting one:
- Industry benchmarks — published patterns (ISO, NCCI, Schedule P aggregates) for the same line, adjusted for differences in limits, mix and case reserving.
- Curve fitting — fit an exponential or inverse-power curve to the observed age-to-age factors and extrapolate the decay. The inverse power curve gives a heavier tail than the exponential and is the more common choice in casualty.
- Bondy method — set the tail equal to the last observed age-to-age factor (or a multiple of it), on the reasoning that development decays geometrically.
- Paid-to-reported convergence — reported losses must eventually equal paid, so the ratio of the two at the oldest maturities implies how much paid development remains.
- Judgment, documented, informed by the settlement characteristics of the line.
- The tail on a paid triangle is larger than on a reported one, since case reserves have already anticipated much of the reported development.
- A tail of exactly
1.000is itself an assumption — that development is complete — and it is the wrong one for any casualty line. Understating the tail is a classic source of reserve deficiency, especially with latent exposures (asbestos, environmental, abuse claims). - Because the tail multiplies the oldest accident years — the ones with the most dollars already reported — a small change in it moves a large reserve. Sensitivity testing the tail is not optional in a long-tail analysis.
Tail Selection Moves the Reserve The last observable age is
120months, with\$2{,}000{,}000reported. Two tail estimates are under consideration:1.030and1.050.Quantify the difference.
Answer
\begin{align*} \text{Tail } 1.030: \; \text{Ultimate} &= \$2{,}060{,}000, \; \text{IBNR} = \$60{,}000 \\ \text{Tail } 1.050: \; \text{Ultimate} &= \$2{,}100{,}000, \; \text{IBNR} = \$100{,}000 \end{align*}Two points of tail is
\$40{,}000on this year — a67\%difference in its IBNR.And the tail applies to every open accident year, not just the oldest. Across ten years of a mature book with
\$20M reported beyond120months, the same two-point difference is\$400{,}000of reserve, arrived at by judgment alone.
Fitting a Tail by Curve Extrapolation Observed age-to-age factors for a workers compensation reported triangle:
Interval Factor 72–841.04084–961.02896–1081.020108–1201.014Estimate the tail beyond
120months.Answer Work with the excess over
1.0, which is what decays:0.040,0.028,0.020,0.014. Successive ratios are
\frac{0.028}{0.040} = 0.70 \qquad \frac{0.020}{0.028} = 0.71 \qquad \frac{0.014}{0.020} = 0.70A clean geometric decay at
r = 0.70. Extrapolating from the last excess of0.014:\begin{align*} \text{Total remaining excess} &= 0.014 \times \frac{0.70}{1 - 0.70} \\ &= 0.014 \times 2.333 \\ &= 0.0327 \end{align*}
\text{Tail} \approx 1.033The Bondy shortcut — take the tail as the last observed factor,
1.014— gives a materially smaller answer, because it captures only one further period rather than the whole infinite remainder.Two cautions. An exponential fit assumes the decay rate holds forever; an inverse power curve, which decays more slowly, would give a heavier tail and is the more conservative choice for a line with latent exposure. And the fit describes the observed pattern — if the last diagonals contain a case strengthening, the fitted decay inherits it.