Stochastic Cape Cod Model
Stochastic Cape Cod Model (SCC) is Meyers' Bayesian version of the Cape Cod model. It is the cross classified (CRC) model without the accident-year parameters, so every accident year has the same expected loss ratio, e^{\mathit{logelr}}, estimated from the data by MCMC.
\mu_{w,d} = \log(\text{Premium}_w) + \mathit{logelr} + \beta_d
C_{w,d} \sim \text{lognormal}(\mu_{w,d},\ \sigma_d)
\sigma_d^2 = \sum_{i=d}^{10} a_i
C_{w,d}is the cumulative loss of accident yearwat development yeard(w, d = 1, \dots, 10). The priors in Meyers (2019), Section 6, are:\mathit{logelr} \sim \text{normal}(-0.4, \sqrt{10})\beta_d \sim \text{normal}(0, \sqrt{10})ford = 1, \dots, 9, with\beta_{10} = 0. The monograph prints a mean of1here; the errata (p.23) corrects it to0.a_i \sim \text{uniform}(0, 1)fori = 1, \dots, 10, which forces\sigma_1^2 > \dots > \sigma_{10}^2
- Where it comes from. In the Bornhuetter-Ferguson method the ultimate is the current loss plus premium times a judgmentally selected expected loss ratio (ELR) times the proportion not yet reported,
V_{11-w}:
\hat C_{w,10} = C_{w,11-w} + \text{Premium}_w \cdot \mathit{ELR} \cdot V_{11-w}
- Stanard and Bühlmann independently proposed estimating the ELR from the data; Bühlmann first presented it at a meeting in Cape Cod. The SCC model estimates it as
\mathit{logelr}. - What it changes from CRC. It drops
\alpha_w, the parameter that lets each accident year's loss ratio differ. That leaves\mathit{logelr}, nine\beta_dand tena_i. - Simulating the outcome. For each of 10,000 posterior parameter vectors, set
\mu_{w,10} = \log(\text{Premium}_w) + \mathit{logelr}and simulate a loss at development year 10. Then subtract the model's expected value of the current reported loss and add the actual current reported loss:
\tilde C_{w,10} = \tilde X_{w,10} - e^{\mu_{w,11-w} + \sigma_{11-w}^2/2} + C_{w,11-w}
- Here
\tilde X_{w,10} \sim \text{lognormal}(\mu_{w,10}, \sigma_{10})andw = 2, \dots, 10. The total isC_{1,10} + \sum_{w=2}^{10} \tilde C_{w,10}. This is the BF structure: actual reported plus expected unreported. The CRC model simulatesC_{w,10}directly. - Results for the illustrative insurer (paid):
e^{\mathit{logelr}} = e^{-0.4033} = 0.668, with a posterior standard deviation of\mathit{logelr}of0.1123against the CRC's0.0233. The\sigma_dare much larger (\sigma_{10} = 0.1051against0.0202). The total paid Estimate is36{,}725with a standard error of3{,}950, against an actual40{,}000(the83.38th percentile). The CRC gives40{,}121with a standard error of2{,}487. - Validation. The SCC performed very poorly on every prospective and retrospective test:
- Its p-p plots fail in every line, paid and incurred. The combined
Dis20.8(paid) and23.2(incurred) against9.6, a "decidedly worse reputation" than the other models. - The standardized residual box plots by accident year were the most revealing. They point to the assumption of a constant expected loss ratio across accident years.
\widehat{elpd}_{loo}favors the CRC model over the SCC for all200paid and all200incurred triangles.\widehat{elpd}_{test}favors CRC for191paid and192incurred triangles.- When lines are paired, failing to capture the accident-year effect distorts the estimated correlation between them; for one insurer it flips from positive to negative. Meyers drops the SCC after that section.
- Its p-p plots fail in every line, paid and incurred. The combined
- A caveat Meyers states. The Bornhuetter-Ferguson and Cape Cod literature stresses adjusting premium to a level consistent with the expected losses, and no such adjustment was made here. The results also show how sensitive the BF method is to that adjustment. The CRC and later models let an actuary influence the ELR by accident year through the priors.
The SCC Estimate Is a Bornhuetter-Ferguson Estimate For accident year
10of Meyers' illustrative paid triangle, premium is4{,}962and the paid loss at development year1is1{,}413. The SCC posterior means are\mathit{logelr} = -0.4033,\beta_1 = -1.0897,\sigma_1 = 0.4608and\sigma_{10} = 0.1051.Using the posterior means as a single parameter set, compute the expected value of the SCC's simulated
C_{10,10}, and show that it is a BF estimate.Answer
\begin{align*} \mu_{10,1} &= 8.50956 - 0.4033 - 1.0897 \\ &= 7.01656 \\ E[\text{reported}] &= e^{7.01656 + 0.4608^2/2} \\ &= e^{7.12273} \\ &= 1{,}240 \\ \mu_{10,10} &= 8.50956 - 0.4033 \\ &= 8.10626 \\ E[\text{ultimate}] &= e^{8.10626 + 0.1051^2/2} \\ &= 3{,}334 \\ E[\tilde C_{10,10}] &= 3{,}334 - 1{,}240 + 1{,}413 \\ &= 3{,}507 \end{align*}Meyers' simulated Estimate for the year is
3{,}506. This is actual paid plus expected unpaid, with an expected ultimate of premium timese^{\mathit{logelr} + \sigma_{10}^2/2} = 0.672. The implied proportion unpaid isV_{10} = 1 - 1{,}240/3{,}334 = 62.8\%, the Bornhuetter-Ferguson formula with an ELR the model estimated.
Why One Loss Ratio Fails In the illustrative paid triangle, accident year
1developed to3{,}912on premium5{,}812, and accident year7to5{,}684on premium4{,}992. The SCC's loss ratio ise^{-0.4033}for every year. The CRC gives accident year7e^{\mathit{logelr} + \alpha_7} = e^{-0.3965 + 0.4354}.(a) Compare the loss ratios.
(b) Meyers reports
\widehat{elpd}_{loo} = -5.14for the SCC and47.80for the CRC on this triangle. Compute each LOOIC and say which is preferred.Answer (a)
\begin{align*} \text{AY 1 actual} &= 3{,}912 / 5{,}812 \\ &= 0.673 \\ \text{AY 7 actual} &= 5{,}684 / 4{,}992 \\ &= 1.139 \\ \text{SCC, every year} &= e^{-0.4033} \\ &= 0.668 \\ \text{CRC, AY 7} &= e^{0.0389} \\ &= 1.040 \end{align*}The SCC fits accident year
1but must give accident year7the same0.668. Its Estimate for that year is4{,}645, against an actual5{,}684. The misfit lands in the residuals, which is why the SCC's\sigma_dare much larger than the CRC's (five times at development year 10) and its accident-year box plots stray from 0.(b)
\begin{align*} \text{LOOIC}_{SCC} &= -2 \times (-5.14) \\ &= 10.28 \\ \text{LOOIC}_{CRC} &= -2 \times 47.80 \\ &= -95.60 \end{align*}The lower LOOIC, the CRC's, is preferred by a wide margin. The SCC has fewer effective parameters (
p_{loo} = 8.75against14.97), but that saving cannot make up for a structure that does not fit the data.