Actuarial Notes

Pure Endowment

Study guide: Exam FAM

A Pure Endowment pays a sum insured at the end of a term of n years if the insured, aged x at issue, is still alive then, and pays nothing if the insured dies first. Its expected present value (EPV) per unit, {}_nE_x, discounts for interest and survival together, so it serves both as a contract in its own right and as the actuarial discount factor that moves life-contingent values through time. It is the survival part of an endowment insurance.

Z = \begin{cases} 0 & K_x \le n-1 \\ v^n & K_x \ge n \end{cases}

{}_nE_x = A^{\phantom{x:}1}_{x:\overline{n}|} = v^n\,{}_np_x

\text{Var}(Z) = v^{2n}\,{}_np_x\,{}_nq_x

{}_{m+n}E_x = {}_mE_x\;{}_nE_{x+m}

  • Symbols: Z = v^n I, where I indicates survival of (x) to age x+n and is a Bernoulli variable with probability {}_np_x. The mean and variance follow, and the second moment is {}^2_{\,n}E_x = v^{2n}\,{}_np_x = v^n\,{}_nE_x. The 1 above \overline{n}| in the second block shows that the term must end before the life fails. The payment time is fixed, so there are no annual, 1/m-thly or continuous versions to convert between.
  • Actuarial discount factor: {}_nE_x moves a value at age x+n back to age x for a life who must survive to collect it. That is how a deferred annuity is valued, {}_{n|}\ddot{a}_x = {}_nE_x\,\ddot{a}_{x+n}, and how a whole life value splits, A_x = A^{1}_{x:\overline{n}|} + {}_nE_x\,A_{x+n}. Dividing by {}_nE_x accumulates instead, so the actuarial accumulated value of an annuity is \ddot{s}_{x:\overline{n}|} = \ddot{a}_{x:\overline{n}|}/{}_nE_x.
  • Part of an endowment: An endowment insurance is a term insurance plus a pure endowment, A_{x:\overline{n}|} = A^{1}_{x:\overline{n}|} + {}_nE_x. The two parts can never both pay, so their present values have covariance -A^{1}_{x:\overline{n}|}\,{}_nE_x. In FAM's objectives, "endowment" covers both this survival benefit and the endowment insurance.
  • Assumptions: {}_nE_x falls when the interest rate rises and rises when mortality is lighter. That is the opposite of a death benefit's response to mortality, which is why survival benefits carry longevity risk.

Twenty-Year Pure Endowment on the SULT A pure endowment of $100,000 is issued to (45) for 20 years. On the SULT, \ell_{45} = 99{,}033.9 and \ell_{65} = 94{,}579.7, and i = 5\%. Find the EPV and the standard deviation of the present value.

Answer {}_{20}p_{45} = 94{,}579.7/99{,}033.9 = 0.95502 and v^{20} = 0.376889.

\begin{align*}
{}_{20}E_{45} &= 0.376889(0.95502) \\
&= 0.359937 \\
\text{EPV} &= 100{,}000(0.359937) \\
&= 35{,}993.70 \\
\text{SD} &= 100{,}000(0.376889)\sqrt{0.95502(0.04498)} \\
&= 37{,}688.9(0.207260) \\
&= 7{,}811.4
\end{align*}

The standard deviation is about 22\% of the EPV. Only 4.5\% of lives forfeit the benefit, so the value of the contract depends mainly on the interest rate.

The Pure Endowment Bought by Annual Premiums A life aged 55 pays $10,000 at the start of each year for 10 years, while alive, to buy a pure endowment payable at age 65. On the SULT at 5\%, \ddot{a}_{55:\overline{10}|} = 8.0192 and {}_{10}E_{55} = 0.59342. Find the pure endowment and compare it with the same deposits saved at 5\% interest.

Answer By the equivalence principle, X\,{}_{10}E_{55} = 10{,}000\,\ddot{a}_{55:\overline{10}|}.

\begin{align*}
X &= \frac{10{,}000(8.0192)}{0.59342} \\
&= 135{,}135.3 \\
10{,}000\,\ddot{s}_{\overline{10}|} &= 10{,}000\,\frac{1.05^{10} - 1}{0.05/1.05} \\
&= 132{,}067.9
\end{align*}

The survivors receive about $3,067 more than a bank account would give. That is their share of the deposits of the 3.3\% of lives who die before 65 and forfeit them, which is the survivorship benefit that the division by {}_{10}E_{55} builds in.

How it appears on the exam

  • FAM asks candidates to identify the present value random variable of a pure endowment and to find its mean, variance or a probability, for example as one part of an endowment insurance or a deferred annuity.
  • Relationships: FAM's objective on the relationships between insurance, endowment and annuity present values uses {}_nE_x to split whole life and annuity values at age x+n, and to find the covariance between the term and pure endowment parts of an endowment insurance.
  • Assumption changes: A question may ask how a value that includes {}_nE_x moves when interest or mortality changes, which tests the opposite response of survival and death benefits.

Exam traps

  • Second moment versus squared mean: The second moment is v^{2n}\,{}_np_x, while the squared mean is v^{2n}({}_np_x)^2. Their difference is the variance, so using one for the other gives a variance of zero.
  • Accumulating at interest only: Dividing by v^n ignores the forfeited deposits of those who die. The actuarial accumulation divides by {}_nE_x, and the gap was about $3,067 in the second example.
  • Converting to continuous: A UDD factor such as i/\delta applies only to death benefits. Applying it to {}_nE_x inside an endowment insurance overstates the value, because the maturity payment is already made at a fixed time.
  • Endowment versus pure endowment: {}_nE_x values a payment on survival only, while A_{x:\overline{n}|} also values the payment on death within the term. Reading "endowment" as one when the question means the other changes the answer by the whole term insurance.