Actuarial Notes

Guaranteed Minimum Maturity Benefit

Study guide: Exam ALTAM

A guaranteed minimum maturity benefit (GMMB) guarantees that a policyholder who is alive at the end of an equity-linked contract's term n receives at least G, so the maturity benefit is \max(G, F_n). The insurer pays (G - F_n)^+ to each survivor, which is a European put on the fund with strike G and expiry n. Its value at issue is the survival probability {}_np_x times a Black-Scholes put on the fund net of all future charges.

\text{Payoff at } n = \mathbb{1}\{T_x > n\}\,(G - F_n)^+

\pi(0) = {}_np_x\left[Ge^{-rn}N(-d_2) - F_0(1-m)^nN(-d_1)\right]

d_1 = \frac{\ln\!\left(F_0(1-m)^n/G\right) + \left(r + \tfrac12\sigma^2\right)n}{\sigma\sqrt{n}}

\begin{aligned} \pi(t) = {}_{n-t}p_{x+t}\big[ & Ge^{-r(n-t)}N(-d_2) \\ & - F_t(1-m)^{n-t}N(-d_1)\big] \end{aligned}

  • Symbols: T_x is the policyholder's future lifetime, F_0 is the premium invested and m is the management charge deducted at the start of each year, so F_n = F_0(1-m)^nS_n/S_0 for an index S. r is the continuously compounded risk-free rate, \sigma is the index's volatility and d_2 = d_1 - \sigma\sqrt{n}. At a later time t, \pi(t) is the value per policy still in force, F_t is the fund before that year's charge, and d_1 and d_2 use F_t(1-m)^{n-t} and the remaining term n - t.
  • Why it is a put: The fund is a fixed number of units of the index, F_0(1-m)^n/S_0 of them by maturity, so the guarantee is a put on those units with strike G. If the charge were taken continuously at rate m, the fund would behave like a stock with dividend yield m, and the put would use F_0e^{-mn} in place of F_0(1-m)^n.
  • The GMAB: A guaranteed minimum accumulation benefit applies the same guarantee at the end of each term of a contract that renews. If the fund is below the guarantee at a renewal date, the insurer tops it up, and the guarantee for the next term is reset, often to the fund value at renewal. Each term is valued like a GMMB, but the reset makes the strikes of later terms depend on the fund's path.
  • Lapses: A policy that lapses before n loses the guarantee. With lapses, {}_np_x is replaced by the probability that the policy is still in force at n, which lowers the cost of the guarantee.

Value of a 10-Year GMMB at Issue A single premium of $100,000 from a life aged 60 is invested in an equity index fund, and a management charge of 1.5\% of the fund is deducted at the start of each year. A policyholder alive at the end of 10 years receives at least $100,000. Use r = 0.04, \sigma = 0.20 and the Standard Ultimate Life Table, for which {}_{10}p_{60} = 0.942549. Find the value of the guarantee at issue.

Answer The put is on 100{,}000(0.985)^{10} = 85{,}973.04, with strike 100{,}000 and expiry 10.

\begin{align*}
d_1 &= \frac{\ln(0.8597304) + 0.06(10)}{0.20\sqrt{10}} \\
&= \frac{-0.15114 + 0.6}{0.63246} \\
&= 0.70972
\end{align*}

So d_2 = 0.07726, N(-d_2) = 0.46921, N(-d_1) = 0.23894 and Ge^{-0.4} = 67{,}032.00.

\begin{align*}
P &= 67{,}032.00\,N(-d_2) - 85{,}973.04\,N(-d_1) \\
&= 31{,}451.97 - 20{,}542.42 \\
&= 10{,}909.55 \\
\pi(0) &= 0.942549(10{,}909.55) \\
&= 10{,}282.79
\end{align*}

The guarantee is worth about 10.3\% of the premium. The insurer has to fund it from the charges, and on this contract it takes most of the 1.5\% charge (see Equity-Linked Insurance).

Value of the Guarantee After a Market Fall Three years after issue, the policyholder in the first example is alive at 63, and the fund has fallen to F_3 = 75{,}000 before the charge for year 4 is taken. Given {}_7p_{63} = 0.953399, find the value of the guarantee per policy in force.

Answer Seven charges remain, so the put is on 75{,}000(0.985)^7 = 67{,}470.65, with 7 years to run.

\begin{align*}
d_1 &= \frac{\ln(0.6747065) + 0.06(7)}{0.20\sqrt{7}} \\
&= \frac{-0.39348 + 0.42}{0.52915} \\
&= 0.05012
\end{align*}

So d_2 = -0.47903, N(-d_2) = 0.68404, N(-d_1) = 0.48001 and Ge^{-0.28} = 75{,}578.37.

\begin{align*}
P &= 75{,}578.37\,N(-d_2) - 67{,}470.65\,N(-d_1) \\
&= 51{,}698.67 - 32{,}386.74 \\
&= 19{,}311.93 \\
\pi(3) &= 0.953399(19{,}311.93) \\
&= 18{,}411.97
\end{align*}

The fall has raised the guarantee's value from $10,283 to $18,412 per policy. A market-consistent reserve for the guarantee rises by the same amount, and so does the hedge the insurer has to hold.

How it appears on the exam

  • ALTAM asks candidates to "define and calculate payoffs" under a GMMB, given a fund path with its charges, and then to value the "guaranteed minimum accumulation/maturity benefit using the Black-Scholes model" at issue or at a later date.
  • Reserving and hedging: The section's aim is to "price, reserve, and hedge" these options, so a question can follow the valuation with the value at a later date, as in the second example, or with the replicating portfolio and its rebalancing cost.
  • Profit testing: In a deterministic profit test the GMMB appears as the top-up (G - F_n)^+ paid to survivors in the final year's cash flow under the stated fund path.

Exam traps

  • The survival weight: The value is the market price of the put times {}_np_x, because only survivors are paid. Leaving out the survival probability overstates the cost, and using a death probability values a GMDB instead.
  • The charges: The put is written on F_0(1-m)^n, not on F_0. Leaving out the charges understates the cost, which falls from $10,282.79 to $7,596.23 in the first example.
  • The rate basis: Black-Scholes needs the continuously compounded rate. Given an effective rate of 4\%, use r = \ln 1.04 = 0.03922 rather than 0.04.
  • A later valuation: At time t, use the remaining term n - t, the survival probability {}_{n-t}p_{x+t} from the policyholder's current age, and the fund net of the charges still to come.