Generalized Pareto Distribution
Study guide: Exam ASTAM
The Generalized Pareto Distribution (GPD) G_{\xi,\beta} is the limiting distribution of the excess loss X - d, given X > d, over a high threshold d, for any loss distribution whose block maxima have a generalized extreme value limit. It is the basis of the peaks-over-threshold method, which fits the GPD to the largest losses only and uses it to estimate tail probabilities, Value at Risk and Expected Shortfall beyond the range of the data.
G_{\xi,\beta}(y) = 1 - \left(1 + \frac{\xi y}{\beta}\right)^{-1/\xi}, \quad \xi \neq 0
G_{0,\beta}(y) = 1 - e^{-y/\beta}
\Pr(X > x) \approx S_X(d)\left[1 + \frac{\xi(x - d)}{\beta}\right]^{-1/\xi}, \quad x > d
Q_\alpha = d + \frac{\beta}{\xi}\left[\left(\frac{S_X(d)}{1 - \alpha}\right)^{\xi} - 1\right]
ES_\alpha = \frac{Q_\alpha + \beta - \xi d}{1 - \xi}
- Symbols: Following Hardy and Saunders (the ASTAM study note on extreme value theory),
\xiis the shape parameter and\beta > 0the scale parameter. The support isy \ge 0when\xi \ge 0and0 \le y \le -\beta/\xiwhen\xi < 0.Q_\alphais the\alpha-Value at Risk andES_\alpha = E[X \mid X > Q_\alpha]the Expected Shortfall, which Loss Models writes as\text{VaR}_pand\text{TVaR}_pfor a continuous loss.S_X(d)is estimated by the proportion of the sample above the threshold. - Pickands–Balkema–de Haan theorem: A distribution is in the maximum domain of attraction of the GEV with shape
\xiif and only if its excess losses overdapproach a GPD with the same\xi, and some scale\beta, asdrises to the top of its range. When\xi > 0the GPD is a two-parameter Pareto with shape1/\xiand scale\beta/\xi, when\xi = 0it is exponential with mean\beta, and when\xi < 0it is bounded. - Linear mean excess: If
YisG_{\xi,\beta}, thenY - kgivenY > kisG_{\xi,\,\beta + \xi k}, so for\xi < 1the mean excess loss atd + kis(\beta + \xi k)/(1 - \xi), a straight line inkwith slope\xi/(1-\xi). The mean is\beta/(1 - \xi)for\xi < 1, and moments exist only below order1/\xi. The threshold is chosen where the empirical mean excess plot becomes roughly linear. - Choosing the threshold: A higher threshold makes the GPD a better approximation but leaves fewer exceedances to fit it to, so the estimate of
\xitrades bias against variance and often has a large standard error.
Peaks Over Threshold for a Liability Book Of 1,000 liability claims, 40 exceed a threshold of 500 (in $000s). A GPD fitted to the 40 excesses has
\xi = 0.4and\beta = 300. Estimate the probability that a claim exceeds 2,000, the 99% Value at Risk and the 99% Expected Shortfall.Answer The threshold's survival probability is estimated as
40/1{,}000 = 0.04, and the GPD supplies the rest of the tail.\begin{align*} \Pr(X > 2{,}000) &= 0.04\left[1 + \frac{0.4(1{,}500)}{300}\right]^{-2.5} \\ &= 0.04\,(3)^{-2.5} \\ &= 0.002566 \\ Q_{0.99} &= 500 + \frac{300}{0.4}\left[\left(\frac{0.04}{0.01}\right)^{0.4} - 1\right] \\ &= 500 + 750(0.741101) \\ &= 1{,}055.83 \\ ES_{0.99} &= \frac{1{,}055.83 + 300 - 0.4(500)}{1 - 0.4} \\ &= 1{,}926.38 \end{align*}The 99% Value at Risk is about $1.06 million, and the claims above it average about $1.93 million. The Expected Shortfall is 1.8 times the Value at Risk, because with
\xi = 0.4the mean excess keeps rising with the threshold.
Reading the GPD Off a Mean Excess Plot Above a threshold of 100, the empirical mean excess function of a set of losses is close to the line
e(100 + k) = 50 + 0.5k. Estimate\xiand\betafor the excess losses over 100, and the probability that a loss above 100 also exceeds 200.Answer A GPD's mean excess line has slope
\xi/(1 - \xi)and intercept\beta/(1 - \xi).\begin{align*} \frac{\xi}{1 - \xi} &= 0.5 \\ \xi &= \tfrac{1}{3} \\ \beta &= 50\left(1 - \tfrac{1}{3}\right) \\ &= 33.33 \end{align*}The excess over 100 must exceed 100, so the conditional probability is
\left[1 + \tfrac{1}{3}(100)/33.33\right]^{-3} = 2^{-3} = 0.125. This GPD is a Pareto with shape 3 and scale 100, so the excess losses have a finite variance but no third moment. A maximum likelihood fit would refine these rough values, but the slope alone already shows a positive\xi.
How it appears on the exam
- ASTAM asks candidates to understand the derivation and characteristics of the GPD and to apply it to the estimation of tail risk measures and probabilities. A question gives a threshold, the number of observations above it out of the sample, and fitted values of
\xiand\beta, then asks for a tail probability, a Value at Risk or an Expected Shortfall.- The exponential case: When
\xi = 0, the formulas take their limits,\Pr(X > x) = S_X(d)\,e^{-(x-d)/\beta},Q_\alpha = d + \beta \ln\big(S_X(d)/(1 - \alpha)\big)andES_\alpha = Q_\alpha + \beta, and the reading's exercises use this case too.- Written comments: The reading's exercises ask for the trade-off in choosing a threshold, and for a comparison of GPD estimates with empirical ones, which cannot go beyond the largest observation.
Exam traps
- Two generalized Paretos: The exam tables from Loss Models list a different "generalized Pareto" with parameters
\alpha,\thetaand\tau, a member of the transformed beta family. The ASTAM objective that pairs the GPD with the GEV means the extreme value distributionG_{\xi,\beta}, and using the tables' entry for a peaks-over-threshold question gives the wrong answer.- Conditional probabilities:
G_{\xi,\beta}gives probabilities for losses that have already exceededd. An unconditional tail probability needs the factorS_X(d), and a Value at Risk needs the tail level1 - \alphaconverted to(1 - \alpha)/S_X(d)above the threshold.- The quantile must lie above the threshold: The formulas for
Q_\alphaandES_\alphahold only when1 - \alpha < S_X(d). A 90% Value at Risk with only 4% of the data abovedcannot come from this tail fit.- A shape of 1 or more: The mean of the GPD, and so the Expected Shortfall, is infinite when
\xi \ge 1. A fitted\xiclose to 1 makes the Expected Shortfall estimate very large and very uncertain.