Actuarial Notes

Decreasing Annuity

Study guide: Exam FM-2

An arithmetic decreasing annuity has payments n, n-1, n-2, \ldots, 1 at the end of periods 1, 2, \ldots, n. Its present value is denoted (Da)_{\overline{n}|}:

(Da)_{\overline{n}|} = \frac{n - a_{\overline{n}|}}{i}

  • The corresponding accumulated value is (Ds)_{\overline{n}|} = (1+i)^n (Da)_{\overline{n}|}.
  • Paired with the increasing annuity, (Ia)_{\overline{n}|} + (Da)_{\overline{n}|} = (n+1)\,a_{\overline{n}|}, since the two payment streams sum to n+1 in every period.
  • For a first payment P decreasing by Q per period (payments P,\, P-Q,\, P-2Q,\, \ldots,\, P-(n-1)Q), the present value is:

PV = P \cdot a_{\overline{n}|} - \frac{Q}{i}\!\left(a_{\overline{n}|} - nv^n\right)

Present Value of Payments 5, 4, 3, 2, 1 A decreasing annuity pays $500,\,\$400,\,\$300,\,\$200,\,\$100 at the end of years 1 through 5. The effective annual rate is i = 6\%. Find the present value.

Answer Factor out 100: PV = 100\cdot(Da)_{\overline{5}|0.06}. a_{\overline{5}|} = 4.2124 (Da)_{\overline{5}|} = \frac{5 - 4.2124}{0.06} = \frac{0.7876}{0.06} \approx 13.1273 PV = 100 \times 13.1273 \approx \$1{,}312.73